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12 m = 10 m v 0 sin 40° t (– 980 m/s2)t2 We can use the first equation to eliminate v 0t from the second and solve for t, which gives t = 367 s When this value is used in the first equation, we get v 0 = 33 m/sExample 7 A rock is released from a height of 196mDetermine (a) the time it spends in air and (b) its speed just before striking the ground Solution Since the rock is not thrown and is only released from rest, the initial speed, v i = 0 If the ( y) axis is taken to be downward, then g = 98m/s 2, and the equation of motion,🔥 K T M L O V E R B O Y 🔥 (@hamid_k_t_m_boy) has created a short video on TikTok with music original sound ️K T M 🔥 L O V E R 🔥 B O Y #bikel #ktmlover #baikuntukharimu #bikelover #backbenchersonflipkart #ktmrc390 Table 1 From Diaquabis Pyridine 2 Carboxamide K 2 N 1 O 2 Nickel Ii Disaccharinate Tetrahydrate Semantic Scholar –VŽå ƒtƒ@ƒbƒVƒ‡ƒ" ƒƒ"ƒY